WebLet the first term, common difference and the number of terms of an AP are a, d and n respectively. Given that, first term (a) = – 5 and last term (l) = 45 Sum of the terms of the AP = 120 ⇒ S n = 120 We know that, if last term of an AP is known, then sum of n terms of an AP is, So, the common difference is 10. WebThe nth term of an arithmetic sequence is given by : an=a1+(n−1)d an = a1 + (n−1)d. To find the nth term, first calculate the common difference, d. Next multiply each term number of the sequence (n = 1, 2, 3, …) by the common difference. Then add or subtract a number from the new sequence to achieve a copy of the sequence given in the ...
nth term of AP - Formula nth Term of Arithmetic Progression
WebAn arithmetic progression or arithmetic sequence (AP) is a sequence of numbers such that the difference from any succeeding term to its preceding term remains constant throughout the sequence. The constant difference is called common difference of that arithmetic progression. For instance, the sequence 5, 7, 9, 11, 13, 15, . . . is an arithmetic progression … WebIn an AP, if the common difference (d) = –4, and the seventh term (a 7) is 4, then find the first term. Advertisement Remove all ads Solution n th term of an AP is T n =a+ (n−1)d For an AP with the first term as 'a' and common difference as 'd', the seventh term is a + 6d. san marin high school nusd
Class 10 Maths Chapter 5 Arithmetic Progression MCQs - BYJU
WebApr 10, 2024 · Assume that a 1, a 2, a 3,… be an arithmetic progression (AP), in which first term a 1 is equal to “a” and the common difference is taken as “d”, then the second term, third term, etc can be calculated as follows:. Second term, a 2 = a+d. Third term, a 3 = (a+d)+d = a+2d,. Fourth term, a 4 = (a+2d)+d = a+3d, and so on.. Therefore, the nth term … WebCorrect option is C) As we know nth term, a n=a+(n−1)d & Sum of first n terms, S n= 2n(2a+(n−1)d), where a & d are the first term amd common difference of an AP. Given, a=5,d=3,a n=50 ⇒a+(n−1)d=50 ⇒5+(n−1)3=50 ⇒5+3n−3=50⇒3n=48⇒n=16 ∴S 16= 216[2a+(16−1)d]=8[2×5+15×3]=440 Hence, n=16,S 16=440 Solve any question of … WebIn the given AP, the first term is a = 7 and the common difference is d = 4. Let us assume that 301 is the n th term of AP. Then: T n = a + (n - 1)d 301 = 7 + (n - 1) 4 301 = 7 + 4n - 4 … san marin high school california